2x^2+10x+12/4x^2-31x+12

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Solution for 2x^2+10x+12/4x^2-31x+12 equation: 


x in (-oo:+oo)

2*x^2+(12/4)*x^2+10*x-(31*x)+12 = 0

2*x^2+(12/4)*x^2+10*x-31*x+12 = 0

5*x^2-21*x+12 = 0

DELTA = (-21)^2-(4*5*12)

DELTA = 201

DELTA > 0

x = (201^(1/2)+21)/(2*5) or x = (21-201^(1/2))/(2*5)

x = (201^(1/2)+21)/10 or x = (21-201^(1/2))/10

x in { (21-201^(1/2))/10, (201^(1/2)+21)/10 }

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